3-78. Because none of the charge is lost, the total charge leaving the battery

during T is equal to the total charge on the line. Therefore:

Q = IT = CE

3-79. As each capacitor accumulates a charge equal to CE, the voltage across

each inductor must change. As C1 in figure 3-23 charges to a voltage of E,

point A rises to a potential of E volts while point B is still at zero volts. This

makes E appear across L2. As C2 charges, point B rises to a potential of E

volts as did point A. At this time, point B is at E volts and point C rises.

Thus, there is a continuing action of voltage moving down the infinite line.

3-80. In an inductor, these circuit components are related, as shown in the

formula--

∆I

E=L

(

)

∇T

3-81. 1-79. This shows that the voltage across the inductor is directly

proportional to inductance and the change in current, but inversely

proportional to a change in time. Because current and time start from zero,

the change in time (∆T) and the change in current (∆I) are equal to the final

time (T) and final current (I). For this case the equation becomes:

ET = LI

3-82. If voltage E is applied for time (T) across the inductor (L), the final

current (I) will flow. The following equations show how T, L, and C are related:

ET = LI

IT = CE

3-83. For convenience, you can find T in terms of L and C by multiplying the

left and right members of each of the above equations, and solving for T, as

follows:

(IT)(ET) = (CE)(LI)

EIT2 = LCEI

T2 = LC

T= LC

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