ANSWER TO FRAME 70.
The diagram would be:
u = 175
Half of the 95% would fall above and half below the mean. So we want to find the value of z
associated with .4750. Searching the table, we find exactly .4750 corresponding to 1.96
standard deviations. Using the modified z equation:
a= u- zσ
b= u + z σ
a = 175 - (1.96) (6)
b = 175 + (1.96) (6)
a = 175 - 11.76
b = 175 + 11.76
a = 163.24
b = 186.76
Thus, we can state the middle 95% of the recruits have heights between 163.24cm and 186.76cm.
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FI0921
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