1.

Available materials: 1- by 6-inch S46

4- by 4-inch S4S

2.

Determine loads: Assume a live load is 50 lb/sf. The dead load is 150 lb/cf.

DL

= 150 (1/2-foot) = 75 psf

LL

= 50 lb/sf

TL

= DL + LL = 125 psf

3.

Go to Table 3-1 on page 3-6 for 1- by 6-inch sheathing for maximum concrete pressure of 125 psf.

Maximum joist spacing is 26 inches.

4.

Uniform load on the joists:

5.

Determine maximum stringer spacing using Table 3-3, page 3-9: 55 inches

6.

Calculate the uniform load on the stringer (ULSstr).

7.

Determine the maximum shore spacing.

From Table 3-3, with a uniform load of 573 lb/ft to 600 lb/ft, the spacing is 37 inches.

Evaluate the maximum shore spacing based on the shore strength. Find supported strength.

10' - 3/4" - 3 1/2" - 3 1/2" = 9' 4 1/2" to the nearest whole number is 10 feet

Allowable load according to Table 3-7 on page 3-21 for the unsupported length of 10 feet is 3,400 (using 4- by 4-

inch S4S).

Evaluate the maximum allowable load based on end-bearing area. (Since the C is unknown, use the lowest

value provided in Table 3-8 on page 3-22.)

Select the allowable load on the shore. (Compare and select the lower.)

Select the most critical spacing which would be 37 inches from using the information above.