ANSWER TO FRAME 70.

The diagram would be:

u = 175

Half of the 95% would fall above and half below the mean. So we want to find the value of z

associated with .4750. Searching the table, we find exactly .4750 corresponding to 1.96

standard deviations. Using the modified z equation:

a= u- zσ

b= u + z σ

a = 175 - (1.96) (6)

b = 175 + (1.96) (6)

a = 175 - 11.76

b = 175 + 11.76

a = 163.24

b = 186.76

Thus, we can state the middle 95% of the recruits have heights between 163.24cm and 186.76cm.